42x^2+30x-12=0

Solution for 42x^2+30x-12=0 equation:

42x^2+30x-12=0

a = 42; b = 30; c = -12;
Δ = b2-4ac
Δ = 302-4·42·(-12)
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2916}=54$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-54}{2*42}=\frac{-84}{84}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+54}{2*42}=\frac{24}{84}
=2/7
$